Here is a nifty way to find remainder on diving numbers:

Remainder on dividing by 3Remainder on dividing by 3

To find the remainder of a number divided by 3, add the digits of the number and divide it by 3. So if the digits added together equal 8 then the number has a remainder of 2 since 8 divided by 3 has a remainder of 2.

For example, find the remainder on dividing 1,342,568 by 3.

The digit sum of 1342568 is 1+3+4+2+5+6+8 = 29.

Again, the digit sum of 29 = 2+9 = 11 = 2

So, the remainder will be 2.

Another example: Take 34,259,677,858.

The digit sum of the number is 3+4+2+5+9+6+7+7+8+5+8 = 64.

Now, the digit sum of 64 is 6+4 = 10 = 1.

So, the remainder is 1.

Similarly, the digit sum of 54,670,329,845 is 53 i.e. (5+3=) 8.

When we divide 8 by 3, we get remainder 2.

So the answer will be 2.

__Remainder on dividing by 4__
To find the remainder of a number divided by 4, take the remainder of the last 2 digits. So if the last 2-digits are 13 then the number has a remainder of 1 since 13 divided by 4 has a remainder of 1.

__Remainder on dividing by 5__
To find the remainder of a number divided by 5, simply use the last digit. If it is greater than 5, subtract 5 for the remainder.

__Remainder on dividing by 7__
Split the digits of the number in group of 3 starting from unit’s place. Add the alternate group and then find their difference. Divide the difference by 7 and get the remainder.

Consider the number 43456827.

Make triplets as written below starting from unit’s place

43.........456..........827

Now alternate sum = 43+827=870 and 456 and difference of these sums =870-456=414. Divide it by 7 we get remainder as 1.

43.........456..........827

Now alternate sum = 43+827=870 and 456 and difference of these sums =870-456=414. Divide it by 7 we get remainder as 1.

Another example, consider the number 4523895099854

Triplets pairs are 4…523…895…099…854

Alternate sums are 4+895+854=1753 and 523+099=622

Difference =1131

Revise the same tripling process 1…131

So difference = 131-1=130

Divide it by 7 we get remainder as 4.

__Remainder on dividing by 8__
To find the remainder of a number divided by 8, take the remainder of the last 3-digits. So if the last 3-digits are 013 then the number has a remainder of 5 since 13 divided by 8 has a remainder of 5.

__Remainder on dividing by 9__
To find the remainder of a number divided by 9, add the digits and then divide it by 9. So if the digits added together equal 13 then the number has a remainder of 4 since 13 divided by 9 has a remainder of 4.

__Remainder on dividing by 10__
To find the remainder of a number divided by 10 simply use the last digit.

__Remainder on dividing by 11__
The difference of the sums of the alternate digits is the remainder after dividing by 11 if it is positive. If the number is negative add 11 to it to get the remainder.

Take the number 34568286 for example.

Sum of alternate digits are 6+2+6+4 = 18 and 8+8+5+3=24

And difference of these sums =18 - 24 = -6.

So, the remainder is -6+11 = 5.

__Remainder on dividing by 13__
Split the digits of the number in group of 3 starting from unit’s place. Add the alternate group and then find their difference. Divide the difference by 13 and get the remainder.

Consider the number 34568276.

Split the number as 34.........568..........276

Now alternate sum = 34+276=310 and 568

and difference of these sums =568-310=258

Divide it by 13 we get remainder as 11

Another example, consider the number 4523895099854

Triplets pairs are 4…523…895…099…854

Alternate sums are 4+895+854=1753 and 523+099=622

Difference =1131

Revise the same tripling process 1…131

So difference = 131-1=130

Divide it by 13 we get remainder as 0

__Remainder on dividing by 27 and 37__
Consider the number 34568276; we have to calculate the reminder on dividing the number by 27 and 37.

Make triplets as written below starting from unit’s place

34.........568..........276

34.........568..........276

Now sum of all triplets = 34+568+276 = 878

Dividing it by 27 we get reminder as 14

Dividing it by 37 we get reminder as 27

Another example for the clarification of the rule; take the number 2387850765.

Triplets are 2…387…850…765

sum of the triplets = 2+387+850+765=2004.

On revising the steps we get 2…004

Sum =6

Dividing it by 27 we get remainder as 6.

Dividing it by 37 we get remainder as 6.

Is there a trick for dividing by 6?

ReplyDeleteNumbers which are divisible by both 2 and 3 are divisible by 6. That is, if last digit of the given number is even and the sum of its digits is a multiple of 3, then the given number is also a multiple of 6.

Deletewhat about other numbers? 24 mod 12 for exple.

ReplyDeleteThere is, but it takes a while.

DeleteNice

ReplyDelete123456789101112131415 divided by 16 Find remainder

ReplyDeleteThe trick for 7 is not applicable if group if 3 middle nos. Is greater than the 2 added nos. In that case remainder will be 7-(remainder obtained by this trick)

ReplyDeleteImpressive man

ReplyDeletehow do you find the remainder for a division with 100

ReplyDelete