The word Digit means the single figure
number; the numbers from 1 to 9 and zero. In mathematics, the

**digit sum**of a given integer is the sum of all its digits, (e.g.: the digit sum of 84001 is calculated as 8+4+0+0+1 = 13).
The

**digital root**(also**repeated digital sum**) of a number is the (single digit) value obtained by an iterative process of summing digits, on each iteration using the result from the previous iteration to compute a digit sum. The process continues until a single-digit number is reached.
To
find digital root of a number, add all its digits. If this sum is more than 9,
add the digits of this sum. The single digit obtained at the end is the digital
root of the number.

For
example, Digital Sum of 24566 is 2+4+5+6+6 = 23 = 2+3 = 5.

Notice that even though sum of the
digit of 24566 is 23, 23 is not the digital sum.
The sum is again added until we are left with a single digit.

Similarly,
the digital root of

**65536**is 7, because 6 + 5 + 5 + 3 + 6 = 25 and 2 + 5 = 7.
In other words, it is the remainder when
the number is divided by 9. So for 625, the remainder is 4 because 625 ÷ 9 = 69
with a remainder of 4. The digital root is also 4 (6+2+5=13=1+3=4).

**A shortcut to**

**find digital root**

**:**

**Casting Out 9’s**

Consider the number 19. The digital sum
of 19 is 1+9 = 10 = 1. Take the number 129. The digital sum of 129 is 1+2+9 =
12 = 3. And, the digital sum of 1239 is 1+2+3+9 = 15 = 6

So, if a number has 9, this will not have
any impact on the digital sum. So, we can safely ignore the digit 9 in the
number.

So, can you guess the digital sum of
599992? Ignoring all the 9’s, we are left with 5 and 2. So the digital sum is
5+2=7.

Consider another example 7486352. Here,
we do not have any 9’s in the number. So, in order to obtain the digital
sum, we will just add all the digits.

Digital Sum of 7486352 is 7+4+8+6+3+5+2
= 35 = 3+5 = 8.

However, there is a shortcut to this procedure. Instead
of adding all the digits, if we find a 9 anywhere in the calculation, we cross it out. This
is called casting out nines. You can see with this example how this removes a
step from our calculations without affecting the result. With the last answer, 7486352,
instead of adding 7+4+8+6+3+5+2, which equals 35, and
then adding 3 + 5, which equals 8, we could cross out group of digits (two or
more) that add up to 9. This makes no difference to the answer, but it saves
some time and effort. So, 6 & 3 add up to 9, so we can cancel
that. Similarly 5 & 4 add up to 9 and 7 & 2 add up to 9.

~~7~~

~~4~~ 8 ~~6~~
~~3~~ ~~5~~
~~2~~

We can cancel all the digits, we are
left with the digit 8. So, the digital sum is 8.

The Digit Sum of

**54****9****6****7****3**is**7**. “Cast out” the**5+4**,**9**and**6+3**, leaving just**7**.
By Casting Out 9’s, finding
a Digit Sum can be done more quickly and mentally!

So, the question
arises,

**why do we need to know Digital Sum of the number?**
It turns out, when the numbers are
added, subtracted, multiplied or divided; their digital sums will also be
respectively added, subtracted, multiplied or divided. So, we can use their
digital sums to check the accuracy of the answer.

**Check any size number**

What makes this method
so easy to use is that it changes any size number into a single-digit number.
You can check calculations that are too big to go into your calculator by
casting out nines.

For instance, if we
wanted to check 12,345,678 × 89,045 = 1,099,320,897,510, we would have a problem because most Checking Your Answers 39 calculators can’t handle
the number of digits in the answer, so most would show the first digits of the
answer with an error sign.

The easy way to check
the answer is to cast out the nines. Let’s try it.

~~1~~

~~2~~

~~3~~

~~4~~

~~5~~

~~6~~

~~7~~

~~8~~

**= 0**

**8 9 0 4 5 = 8**

**1**

**0**

**9**

**9**

**3**

**2**

**0**

**8**

**9**

**7**

**5**

**1**

**0 = 0**

All of the digits in the
answer cancel. The nines automatically cancel, then we have 1 + 8, 2 + 7, then
3 + 5 + 1 = 9, which cancels again. And 0 × 8 = 0, so our answer seems to be correct.

Let’s try another one.

137 × 456 = 62,472

To find our substitute
for 137:

1 + 3 + 7 = 11

1 + 1 = 2

There were no shortcuts
with the first number. 2 is our substitute for 137.

To find our substitute
for 456:

4 + 5 + 6 =

We immediately see that
4 + 5 = 9, so we cross out the 4 and the 5.

That just leaves us with
6, our substitute for 456.

Can we find any nines,
or digits adding up to 9, in the answer?

Yes, 7 + 2 = 9, so we
cross out the 7 and the 2. We add the other digits:

6 + 2 + 4 = 12

1 + 2 = 3

3 is our substitute
answer.

Writing the substitute numbers below
the actual numbers might look like this:

**137 × 456 = 62,472**

**2 6 3**

Is 62,472 the right
answer?

We multiply the
substitute numbers: 2 times 6 equals 12. The digits in 12 add up to 3 (1 + 2 =
3). This is the same as our substitute answer, so we were right again.

Let’s try one more
example. Let’s check if this answer is correct:

456 × 831 = 368,936

We write in our
substitute numbers:

**456 × 831 = 368,936**

**6 3 8**

That was easy because we
cast out (or crossed out) 4 and 5 from the first number, leaving 6. We cast out
8 and 1 from the second number, leaving 3. And almost every digit was cast out
of the answer, 3 plus 6 twice, and a 9, leaving a substitute answer of 8.

We now see if the
substitutes work out correctly: 6 times 3 is 18, which adds up to 9, which also
gets cast out, leaving 0. But our substitute answer is 8, so we have made a
mistake somewhere.

When we calculate it
again, we get 378,936.

Did we get it right this
time? The 936 cancels out, so we add 3 + 7 + 8, which equals 18, and 1 + 8 adds
up to 9, which cancels, leaving 0. This is the same as our check answer, so
this time we have it right.

**Does this method prove we have the right answer?**No, but we can be almost certain.

This method won’t find

*all*mistakes. For instance, say we had 3,789,360 for our last answer; by mistake we put a 0 on the end.
The final 0 wouldn’t
affect our check by casting out nines and we wouldn’t know we had made a
mistake. When it showed we had made a mistake, though, the check definitely
proved we had the wrong answer.

Again, we
know from the last example, the Digital sum of 378,936 is 0 and the digital
sum of 387,936
(which we might have put mistakenly) is also 0. In this case, even though the
numbers are different, the Digital sum remains the same as the numbers have changed
their places.

So, even digital root technique helps us
in eliminating few options (if any, as in case of MCQ) from the question, it
cannot conclusively point out the right answer. It is a simple, fast check that will find
most mistakes, and should get you 100% scores on most of your math tests.

nice

ReplyDeletegood tutorial

ReplyDeletePlease add a tutorial for Prime numbers also .

ReplyDeleteApply for 2693÷36=73.75. Or 975+714÷42

ReplyDeleteIs this method is not apply for all simplification?

2655/36=73.75

DeleteApply this method for 2637÷36=77.25. Or. 975+714÷42=992

ReplyDeleteAdd more detailed tutorial

ReplyDeleteAdd more detailed tutorial

ReplyDeleteSir (1.56)^2 = digital root method me kitna hoga?

ReplyDelete9

Delete1.56×1.56=3×3 =9

DeleteOut of 50 problems in SBI PO exams how many problems can be solved with Digit sum?

ReplyDelete689*2/4+781/12=13526/8+? Plz solve with

ReplyDeleteThis method

5*5+(781+90)/12=6763/4+x

Delete7+871/12=6763/4+x

7+6+91/12=169+6/4+x

7+6+7=7+6+x

2=4+x

X=-2

X=7

Give some fractions based prob n solve

ReplyDeletenice

ReplyDelete1000-2= 998

ReplyDeleteDigit sum,

1-2=8

-1=8..???

Plz clarify me frnds

1000-2= 998

DeleteDigit sum,

1-2=8

1=8+2

1=10

1=1

-1+9=8(adding 9 won't affect so we add 9 to eliminate

Delete- sign)

1000-2=998

Delete1-2=8

-1=8

When we get a minus digital root then you have to minus from 9 to get final digital root. In this case

9-1=8

8=8

Digital sum = -1 is equivalent to saying Digital sum == -1+9=8 since the arithmetic used to prove the addition of digital sum is Modulo Arithmetic.

DeleteModulo Arithmetic is arithmetic of remainders

Digital sum ==remainder of the number when divided by 9

Since remainder of -1 is equivalent to 8 we may state them congruent

X=-a

DeleteThen x=-a+9(actual digital root)

this technique won`t work for division but still make the division approximately and apply digital root sum technique....

ReplyDeleteaccording to the title the blog it is really 'burning math'

ReplyDelete